Home Physics Surface Tension JEE (Advanced) / IIT-JEE Problems (Previous Years) A glass tube of uniform internal radius (r) …
Physics Surface Tension JEE (Advanced) / IIT-JEE Problems (Previous Years) MCQ (Single Correct)

A glass tube of uniform internal radius (r) has a valve separating the two identical ends. Initially, the valve is in a tightly closed position. End 1 has a hemispherical soap bubble of radius r. End 2 has sub-hemispherical soap bubble as shown in figure. Just after opening the valve,

A
air from end 1 flows towards end 2. No change in the volume of the soap bubbles
B
air from end 1 flows towards end 2. Volume of the soap bubble at end 1 decreases
C
no change occurs
D
air from end 2 flows towards end 1. Volume of the soap bubble at end 1 increases.

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Text Solution

Verified by Experts
The correct answer is:
B

Pressure inside tube = P = P 0 +

∴ P 2 < P 1 (since r 2 > r 1 )

Hence pressure on side 1 will be greater

than side 2. So, air from end 1

flows towards end 2.

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